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The size of incomplete planchets..

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  • Maxorin
    • Dec 2007
    • 34

    The size of incomplete planchets..

    Is there an easy way to calculate exactly how much of a coin is missing, in %?
  • diamond
    • Jul 2007
    • 2040

    #2
    Sure, weigh it to the nearest tenth of a gram and see how much is missing relative to a coin of normal weight.
    Mike Diamond. Error coin writer and researcher.

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    • Maxorin
      • Dec 2007
      • 34

      #3
      Thank you.

      Is there other ways to calculate it or is weight the way to go?
      I`m thinking slabbed coins for example could be hard to weigh
      like that. And coins you have pics of, but you dont have the
      coin itself.

      Comment

      • diamond
        • Jul 2007
        • 2040

        #4
        You're never going to get an accurate percentage weight loss from a photo or from inside a slab. Metal expands under the force of the strike, and this often reduces the size of the original clip. Inaccuracy is greatest when the coin is struck out-of-collar, when there are multiple clips involved, when the clip is extremely small or extremely large, or when the clip is irregular.
        Mike Diamond. Error coin writer and researcher.

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        • Maxorin
          • Dec 2007
          • 34

          #5
          Ok, thanks, had a feeling it could be hard to get done but started wondering if there could be some math formula to figure it out with.

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          • diamond
            • Jul 2007
            • 2040

            #6
            Try this: To find the area of a curved clip, use the following formula: pi X w X d / 4 with w = maximum width and d = diameter.

            All I'm saying is that any answer you get provides precision without accuracy.
            Mike Diamond. Error coin writer and researcher.

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            • 19Lyds
              • Aug 2007
              • 240

              #7
              Originally posted by diamond View Post
              Try this: To find the area of a curved clip, use the following formula: pi X w X d / 4 with w = maximum width and d = diameter.

              All I'm saying is that any answer you get provides precision without accuracy.
              I've been wondering about this for a long time Mike and now wish I hadn't failed basic Algebra!
              Lee Lydston

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